A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet, their respective kinetic energies will be in the ratio of

\sqrt{2} : 1

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1 : 2

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1 : 2

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1 : \sqrt{2}

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Solution

The correct option is C $1 : 2$
Given mass of ball 1, $m_{1}$ = 2 kg
Give mass of ball 2, $m_{2}$ = 4 kg
Since the balls are dropped at the same time, the change in velocity is equal in ball 1 and ball 2. (As the balls fall with an acceleration due to gravity $10 m s^{- 2}$ )
$\frac{(K . E)_{1}}{(K . E)_{2}} = \frac{m_{1}}{m_{2}} = \frac{2}{4}$
or, $(K . E)_{1} : (K . E)_{2} = 1 : 2$

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A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet, their respective kinetic energies will be in the ratio of

The correct option is C 1:2Given mass of ball 1, m1 = 2 kg Give mass of ball 2, m2 = 4 kg Since the balls are dropped at the same time, the change in velocity is equal in ball 1 and ball 2. (As the balls fall with an acceleration due to gravity 10 ms−2) (K.E)1(K.E)2=m1m2=24 or, (K.E)1:(K.E)2=1:2