CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball of mass 2 kg is connected to a string of length 1 m and made to move in a horizontal circle on a smooth frictionless table with a constant speed of 2 m/s. The other end of the string is connected to a fixed peg on the table. Find the magnitude of the average impulse exerted by the string on the ball in half a revolution:

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8 Ns
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
22 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 8 Ns
Velocity of the ball at a particular point of the circular path Vi=2 m/s
Velocity of the ball at its diametrical opposite point of the path Vf=2 m/s
Mass of ball m=2 kg
Change in momentum of the ball |ΔP|=|mVfmVi|
|ΔP|=(2)|22|=8kg m/s
Impulse I=ΔP=8 Ns

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Momentum Returns
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon