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Question

A ball of mass 2kg is connected to a string of length 1m and made to move in a horizontal circle on a smooth frictionless table with a constant speed of 2m/s. The other end of the string is connected to a fixed peg on the table. Find the magnitude of the average impulse exerted by the string on the ball in half a revolution.
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A
0
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B
8Ns
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C
4Ns
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D
22Ns
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Solution

The correct option is B 8Ns
Initial momentum, Pi=mv^j
After half revolution, final momentum, Pf=mv^j
Impulse J=PfPi
J=2mv^j
Given: m=2kg; v=2m/s
Thus |J|=2×2×2=8 Ns

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