A ball of mass 2kg is dropped from a height of 20m. After striking the ground, the ball bounces back with half of its striking speed. Find the impulse imparted by the normal reaction from the ground. Take g=10m/s2.
A
40N-s
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B
80N-s
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C
0N-s
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D
60N-s
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Solution
The correct option is D60N-s Ball is dropped from 20m height, therefore it reaches the ground with speed v0. |v0|=√2gh=√2×10×20 =−20m/s (consider upward direction as positive)
Let v1 be the speed at which it bounces back Given v1=v02=10m/s