A ball of mass $200 g$ falls from a height of $5 m$ . What is its K.E. when it just reaches the ground ?

9.8 J

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98 J

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980 J

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None of these

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Solution

The correct option is A $9.8 J$
Given,
$M = 200 g = .2 k g, h = 5 m$
From conservation of energy,
Gain in kinetic energy $K . E =$ loss in $P . E$
initial P.E $=$ mgh
initial K.E $= 0$
final P.E $= 0$
$K . E_{f} - K . E_{i} = P . E_{i} - P . E_{f}$
$K . E_{f} - 0 = 0.2 \times 9.8 \times 5 - 0 K . E_{f} = 9.8 J$

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