CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20 m. Find the time for which the ball remains in contact with the bat.

A
0.12s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.24s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.36s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.48s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.12s
M=0.4gm =0.4kg
h1=5m , h2=20m
g=10m/s2
Velocity of the ball after dropping 5m:u
Velocity of the ball after being hit by the bat:v
u2=2gh1;u=(2×10×5)=10m/s(downwards)

v2=2gh2;(2×10×20)=v=20m/s(upwards)

Change of momentum =impulse= m(v+u)=12kgm/s
Force=100N=12/t
t= time of contact =0.12sec
Hence,
option (A) is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
F=ma
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon