Question

A ball of mass 50 g is thrown vertically upwards with an initial velocity $20m{s}^{-1}$. Calculate the maximum potential energy it gains as it goes up.

Answer 1

Given that,

$m=0.05$ and $v=20m/s^1$

Maximum potential energy at highest point= Initial kinetic energy at the bottom point

$\therefore$Maximum potential energy $=\frac{1}{2}m{v}^2$

$\begin{array}{c}=\frac{1}{2}\times 0.5\times 20\times 20\\ =\frac{200}{2}\\ =100J\end{array}$