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Question

A ball of mass 500 g strikes a fixed wall with a speed of 10 m/s. After striking, it returns back with the same speed. Find the magnitude of the change in momentum of the ball.

A
0 kg m/s
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B
5 kg m/s
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C
10 kg m/s
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D
15 kg m/s
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Solution

The correct option is C 10 kg m/s
Initial momentum, pi = m x vi = 0.5 kg x 10 m/s = 5 kg m/s

After the collision with the wall, the velocity of the ball becomes opposite to the initial velocity.
⇒ Final velocity, vf = -10 m/s
Here, the negative sign implies the opposite direction.

Final momentum, pf = m x vf
= 0.5 kg x (-10 m/s) = -5 kg m/s

Change in momentum, Δp = pf - pi
⇒ Δp = - 5 - 5 = - 10 kg m/s
Magnitude of the change in momentum = 10 kg m/s

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