A ball of mass 500g is initially at rest at the bottom most point of a smooth vertical circular track of radius 10m. For looping a loop, the minimum kinetic energy the ball should have at the bottommost point on the track is
A
100J
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B
125J
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C
250J
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D
1250J
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Solution
The correct option is B125J Let the velocity of the ball at the bottom of the track be vA
The minimum velocity at the bottom for completing the loop is given by, vbottom=vA=√5gl
⇒vA=√5×10×10=10√5m/s
Hence the minimum kinetic energy at the bottom most point on the track is given by, K.E=12mv2A=12×0.5×(100×5)