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Question

A ball of mass 600 g strikes a wall with a velocity of 5ms1 at an angle 30 with the walls and rebounds with the same speed at the same angle with the wall. The magnitude of change in momentum of the ball is. (in kg ms1)

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Solution

Given that,

m=600g=0.6Kg

Velocity, v=5m/s

Since, the ball bounces with same velocity and with same angle.

So, usinθ=vsinθ

So, change in momentum,

Δp=musinθ(mvsinθ)

=2mvsinθ

=2×0.6×5×sin30

Δp=3Kgm/s

Change in momentum is 3Kgm/s


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