The correct option is
A P-1; Q-3; R-2; S-4
Buoyant force on ball =
√2(2mg) Force on ball w.r.t. vessel, where
Fp is peudo force on ball in frame of vessel.
Since, force on ball in frame of vessel is along upward normal to surface of liquid,ball will rise.
(P) - 1, 3, 4
Buoyant force on ball
=vρ(g+g)=4mg Force on ball w.r.t vessel
Since, force on ball in frame of vessel is along upward normal to surface of liquid, ball will rise.
(Q) - 3, 4
Buoyant force on ball
=vρ(g−g)=0 Force on ball w.r.t. vessel is absent.
Since, force on ball in frame of vessel is zero, ball will remain stationary.
(R) - 2
Since, acceleration of vessel is
g/2 downwards. Therefore,
Buoyant force on ball
=vρ√(g/2)2+(g)2+2(g)(g/2)cos120∘=√3mg Since, force on ball in frame of vessel is along upward normal to surface of liquid, ball will rise.
(S) - 3, 4