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A ball of mass m is attached to the lower end of a light vertical spring of force constant k. The upper end of the spring is fixed. The ball is released from rest with the spring is at its natural length. The ball comes to rest momentarily after descending through a distance y. At this position, acceleration of the ball is

A
Zero
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B
g downward
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C
g upward
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D
2g upwards
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Solution

The correct option is C g upward

Since non-conservative forces are absent,
Ki+Ui=Kf+Uf
0+0=0+12ky2mgy
y=2mgk
FBD at f.
kymg=ma
k[2mgk]mg=ma
a=g,upwards.

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