The correct option is C 1:3
Total mechanical energy at height, H
EH=mgH
Let vh be velocity of the ball at height h(=34H)
∴ Total mechanical energy at height h,
Eh=mgh+12mv2h
According to law of conservation of mechanical energy,
EH=Eh;mgH=mgh+12mv2h
v2h=2g(H−h)
Required ratio of kinetic energy to potential energy at height h is
KhVh=12mv2hmgh=12m2g(H−h)mgh=(Hh−1)=13.