Question

A ball of mass $m$ is moving on a circular path with angular velocity $\omega$ and tangential acceleration $a_t$ as shown in the figure. What will be the direction of net force acting on the body at point $C$?

• A. Along CF
• B. Along CA
• C. Along CG
• D. Along CB

Answer 1

The correct option is C Along CG

At point C,
$a_c=R{\omega }^2$
& $a_t=a_t\left(\text{given}\right)$
$\because a_c\perp a_t$, $a_{net}=\sqrt{a_t^2+a_c^2}$
i.e $\tan \theta =\frac{a_t}{a_c}$


Hence, net force can act along CG shown in figure.