A ball of mass ′m′ is projected from the ground with a speed ′u′ at an angle ' α' with the horizontal. The magnitude of the change in momentum of the ball over a time interval in which it reaches the maximum height is :
A
musinα
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2mucosα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
mucosα2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2musinα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Amusinα The velocity of the ball along the x-direction does not change ∴△vx=0⇒△px=0 Initial velocity along y-direction=usinα⇒pyinitial=musinα^j Velocity along y-direction at topmost point =0⇒pyfinal=0 ∴△py=−musinα^j ∴△p=△px+△py=−musinα^j ⇒ Change in magnitude of momentum =musinα