Question

A ball of mass $m$ is projected from the ground with an initial velocity $u$ making an angle of $\theta$ with the horizontal. What is the change in velocity between the point of projection and the highest point?

• A. $usin\theta$
• B. $u^{2}cos\theta$
• C. $ucos\theta$
• D. $u^{2}sin\theta$

Answer 1

The correct option is A $usin\theta$

As the projectile moves upwards vertical component of velocity changes only, there will be no effect on the horizontal component of velocity.

When velocity is broken in horizontal ($uCos\theta$) and vertical ($Sin\theta$) components then only vertical components decreases up to zero at peak point and then starts decreasing in Negative direction.

So change in velocity in between top and point of projection is $uSin\theta -0$. I.e.$uSin\theta$.