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Question

A ball of mass m is projected upward from a tower with velocity 30 m/s and at the same time, another ball of mass 2m is dropped from rest from the same tower. Find the displacement of the COM in 2 s. [Take g=10 m/s2]

A
0 m
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B
10 m
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C
5 m
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D
7.5 m
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Solution

The correct option is A 0 m
Given, u1=30 m/s (upwards)
and u2=0

We know,
ucom=u1m1+u2m2m1+m2
=30×m+0×2mm+2m=10 m/s
Acceleration of both the balls is g, therefore acceleration of COM will be -g
Let the displacement of COM be d. Then in 2 s,
d=ucomt+12acomt2
=10×2+12(10)×22
=0

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