Derivation of Velocity-Time Relation by Graphical Method
A ball of mas...
Question
A ball of mass m is thrown straight upward from the top of a multi-storey building with an initial velocity of 15m/s. Find out the time taken by the ball to reach its maximum height?
A
25s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
15s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
1.5s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is E1.5s Given : initial velocity u=15m/s
acceleration a=−g=−10m/s2 (taking upward direction to be positive)
Final velocity of the ball at the highest point v=0m/s