A ball of mass $m$ is thrown straight upward from the top of a multi-storey building with an initial velocity of $15 m / s$ .
Find out the time taken by the ball to reach its maximum height?

25 s

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15 s

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10 s

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5 s

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1.5 s

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Solution

The correct option is E $1.5 s$
Given : initial velocity $u = 15 m / s$
acceleration $a = - g = - 10 m / s^{2}$ (taking upward direction to be positive)
Final velocity of the ball at the highest point $v = 0 m / s$

Using the first equation of motion $v = u + a t$
$∴$ $0 = 15 + (- 10) t$
$⟹ t = 1.5 s$

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A ball of mass m is thrown straight upward from the top of a multi-storey building with an initial velocity of 15 m/s.Find out the time taken by the ball to reach its maximum height?

The correct option is E 1.5 sGiven : initial velocity u=15 m/s acceleration a=−g=−10m/s2 (taking upward direction to be positive)Final velocity of the ball at the highest point v=0 m/s Using the first equation of motion v=u+at∴ 0=15+(−10)t ⟹t=1.5 s

A ball of mass $m$ is thrown straight upward from the top of a multi-storey building with an initial velocity of $15 m / s$ .
Find out the time taken by the ball to reach its maximum height?