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Question

A ball of mass 'm' moves normal to a wall with a velocity 'u' and rebounds with a velocity 'v'. The change in momentum of the ball is (surface of the wall is smooth):

A
m(u+v) towards the wall
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B
m(uv) towards the wall
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C
m(u+v) away from the wall
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D
m(uv) away from the wall
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Solution

The correct option is B m(u+v) away from the wall

A ball of mass, m, moving with initial velocity, u to the right towards a wall.
It will have momentum pi=mu towards the right.

The ball bounces off the wall. It will now be moving to the left, with the same mass, but a different velocity, v and therefore, a different momentum,pf=mv towards the left.

The final momentum vector must be the sum of the initial momentum vector and the change in momentum vector, p=mv .

Using tail to head vector addition, p, must be the vector that starts at the head of pi and ends on the head of pf, hence the resultant change in momentum vector will point towards the left, that is, away from the wall.

We also know from algebraic addition of vectors that:
pf=pi+p

pfpi=p

Magnitude of the change in momentum = mv(u)=m(v+u)
Direction of change in momentum is towards the left, away from the wall.
318012_3079_ans.jpg

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