A ball of mass m moving at a speed v makes a head on collision with an identical ball at rest. The kinetic energy at the balls after the collision is 3/4th of the original. What is the coefficient of restitution?
A
1/√3
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B
1/√2
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C
√2
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D
√3
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Solution
The correct option is A1/√2 Since, we know that in the case, when m1=m2 and v1=0 then,
v′1=(1+e2)v2 and v′2=(1−e2)v2 Given that, KF=34Ki ⇒12mv′21=12mv′22=34(12mv2) Substituting the values, we get (1+e2)2+(1−e2)2=34 ⇒(1+e)2+(1−e)2=3 ⇒2+2e2=3⇒e2=12⇒e=1√2