A ball of mass m moving with a velocity v hits a massive wall of mass M(M>>m) moving towards the ball with a velocity u. An elastic impact lasts for a time Δt.
A
The average elastic force acting on the ball is m(u+v)Δt
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B
The average elastic force acting on the ball is 2m(u+v)Δt
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C
The kinetic energy of the ball increases by 2mu(u+v)
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D
The kinetic energy of the ball remans the same after the collision.
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Solution
The correct options are B The average elastic force acting on the ball is 2m(u+v)Δt C The kinetic energy of the ball increases by 2mu(u+v)
Let v′ be velocity of the ball after collision, away from the wall. In an elastic collision vsep=vapp v′−u=v+u v′=v+2u Change in momentum of ball is |pf−pi =|m(−v′)−mv| =m(v′+v) =2m(u+v) average force =ΔpΔt=2m(u+v)Δt Change in KE = Kf−Ki=12mv′2−12mv2=m2((v+2u)2−v2)=m2((2v+2u)2u) The kinetic energy of the ball increases by 2mu(u+v)