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Question

A ball of mass m strikes a rigid wall speed u at an angle u at an angle of 300 and ger reflected with the same speed and at the same angle as shown in the figure. If the ball is in contact with the wall for time t, then the force acting on the wall is
939250_d5fad26722f340909baca6e78b571170.png

A
mu sin300t
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B
2mu sin300t
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C
mu cos300t
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D
2mu cos300t
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Solution

The correct option is C 2mu cos300t
Initial momentum of the ball is
¯¯¯¯pi=mu cos300^imu sinθ^j
Final momentum of the ball is
¯¯¯¯¯pf=mu cos300^imu sinθ^j
change in momentum,
¯¯¯pf¯¯¯pi=2mu cos300^i
Impulse = change in momentum =2mu cos300^i
As impulse and force are in the same direction, therefore, force on the ball due to the wall is normal to the along the negative x-axis. Using Newton's 3rd law of motion the wall due to the ball is normal to the wall along the positive x-direction.
F=2mu cos300t


1032381_939250_ans_a8287ea1d7e04fcfbaf0e8dde379460f.png

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