A ball of mass m strikes the fixed inclined plane after falling through a height h. If it rebounds elastically, the impulse imparted on the ball is
A
2m√2ghcosθ
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B
2m√ghcosθ
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C
2m√2ghsinθ
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D
2m√2gh
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Solution
The correct option is A2m√2ghcosθ Speed of ball just before the collision u=√2gh Collision is elastic hence, e=1 e=(Velocity of seperationVelocity of approach)along line of impact
⇒e=vucosθ ⇒v=eucosθ=ucosθ∵e=1
Here, v is the velocity component of ball just after collision along line of impact. Impulse J=ΔP=mv−(−mucosθ) ⇒ΔP=mucosθ+mucosθ ⇒J=ΔP=2mcosθ√2gh