Question

A ball of thermal capacity $10cal{/}^{\circ }C$ is heated to the temperature of furnace. It is then transferred into a vessel containing water. The water equivalent of vessel and the contents is $200g$. The temperature of the vessel and its contents rises from ${10}^{\circ }C$ to ${40}^{\circ }C$. What is the temperature of furnace?

• A. ${640}^{\circ }C$
• B. ${64}^{\circ }C$
• C. ${600}^{\circ }C$
• D. ${100}^{\circ }C$

Answer 1

The correct option is A ${640}^{\circ }C$

Let the temperature of the furnace be $T^{o}C$
Then, heat absorbed by vessel= heat released by the ball
$\Rightarrow 200\times 30=10(T-40)$
$\Rightarrow T={640}^{o}C$