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Question

# A ball rises to surface at a constant velocity in liquid whose density is 4 times greater than that of the material of the ball. The ratio of the force of friction acting on the rising ball and its weight is :

A
3:1
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B
4:1
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C
1:3
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D
1:4
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Solution

## The correct option is A 3:1Frictional Force=4πr33(d1−d2)gWeight=4πr33(d1g)where d1 is density of balld2 is density of liquidGiven:d2=4d1Frictional Force=4πr33(d1−4d1)g=4πr33(−3d1)gConsidering only magnitude of frictional force because its already known that both forces act in opposite directions.Frictional Force=34πr33(d1g)=3× WeightTherefore the correct opton is (A).

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