A ball rolls off the top of a star way with a horizontal velocity 10√10. If the steps are 0.25 m high and 5 m wide then the ball will hit the edge of the nth step where n is
A
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 2 We know horizontal distance covered by the ball=nb where n=number of steps and b=breadth of the step.
So v=nbt
t=5n10√10
And vertical distance covered by the ball =nh where h= height of the step.
Now from equation of motion we get
s=ut+12gt2 here s=nh and u= initial velocity = 0 m/s