A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its center of mass is k. If radius of the ball is R, then the fraction of total energy associated with its rotational energy will be
A
k2k2+R2
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B
R2k2+R2
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C
k2+R2R2
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D
k2R2
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Solution
The correct option is Ak2k2+R2 RE=12mK2ω2 TE=12mR2ω2+12mk2w2