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Question

A ball (solid sphere) of mass m is rolling on a smooth horizontal surface as shown in figure. At an instant the magnitude of the velocity of the centre of mass is v0 and its angular velocity is ωv02R, where R is the radius of the ball. The total kinetic energy of the rolling ball at this instant is:-
1129566_b406021e19034b4e9bfc90ad50aa5dd9.png

A
75mR2ω20
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B
115mR2ω20
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C
1120mv20
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D
720mv20
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Solution

The correct option is C 1120mv20
KE=12mv02+12(2mR25)w2
=12mv02+mR25v024R2
=12mv02+mv0220
=11mv0220
Hence,
option (C) is correct answer.

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