A ball starts rolling on a horizontal surface with an initial velocity of $1 m / s .$ Due to friction, its velocity decreases at the rate of $0.1 m / s^{2}$ . How much time will it take for the ball to stop?

1 s

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100 s

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10 s

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0.1 s

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Solution

The correct option is A 10 s
In the given question, we have
$u = 1 m / s$
$a = - 0.1 m / s^{2}$ (negative sign indicates that the direction of acceleration is opposite to the initial velocity)
As the ball finally stops,
$v = 0$
$t = ?$
According to first equation of motion,
$v = u + a t$
$\Rightarrow 0 = 1 + (- 0.1) t$
$\Rightarrow 1 = 0.1 t$
So $t = 10 s e c$
Option C is correct.

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A ball starts rolling on a horizontal surface with an initial velocity of 1 m/s. Due to friction, its velocity decreases at the rate of 0.1m/s2. How much time will it take for the ball to stop?

A ball starts rolling on a horizontal surface with an initial velocity of $1 m / s .$ Due to friction, its velocity decreases at the rate of $0.1 m / s^{2}$ . How much time will it take for the ball to stop?