A ball starts to roll over a horizontal surface with an initial velocity of $0.5 m / s$ . Due to friction, it stopped after 10 seconds. Calculate the acceleration of the ball.

0.5 m / s^{2}

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0.05 m / s^{2}

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- 0.5 m / s^{2}

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- 0.05 m / s^{2}

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Solution

The correct option is D $- 0.05 m / s^{2}$
Given : u = $0.5 m / s$ ; v = $0 m / s$ ; t = 10 sec
Using 1st equation of motion
v - u = at
0 – 0.5 = a x 10
=> a = $- 0.05 m / s^{2}$

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A ball starts to roll over a horizontal surface with an initial velocity of 0.5 m/s. Due to friction, it stopped after 10 seconds. Calculate the acceleration of the ball.

The correct option is D −0.05 m/s2Given : u = 0.5 m/s ; v = 0 m/s ; t = 10 sec Using 1st equation of motion v - u = at 0 – 0.5 = a x 10 => a = −0.05 m/s2

A ball starts to roll over a horizontal surface with an initial velocity of $0.5 m / s$ . Due to friction, it stopped after 10 seconds. Calculate the acceleration of the ball.

The correct option is D $- 0.05 m / s^{2}$
Given : u = $0.5 m / s$ ; v = $0 m / s$ ; t = 10 sec
Using 1st equation of motion
v - u = at
0 – 0.5 = a x 10
=> a = $- 0.05 m / s^{2}$