Question

A ball thrown by one player reaches the other in $2s$. The maximum height attained by the ball above the point of projection will be about:

• A. $2.5m$
• B. $5m$
• C. $7.5m$
• D. $10m$

Answer 1

The correct option is B $5m$

Time of flight of projectile is $t=\frac{2u\sin \theta }{g}$

$2=\frac{2u\sin \theta }{g}$

$\Rightarrow u\sin \theta =g......\left(1\right)$

Maximum height of projectile

$h_{max}=\frac{u^2{\sin }^2\theta }{2g}$

Put value from equation (1)

$h_{max}=\frac{g^2}{2g}=5m$

Maximum height of projectile is $5m$