Question

A ball thrown by one player reaches the other in $2s$. The maximum height attained by the ball above the point of projection will be ($g=10m/s^2$)

• A. $5m$
• B. $13m$
• C. $3m$
• D. None of these

Answer 1

Answer: (A)

$5m$

Time of flight $T=2$ s

Time of flight $T=\frac{2u_y}{g}$ $⟹u_y=\frac{Tg}{2}$ ........(1)

Maximum height $H_{max}=\frac{u_y^2}{2g}$ .......(2)

Using (1) in (2), we get $H_{max}=\frac{T^{2}g}{8}$

$⟹$ $H_{max}=\frac{2^2\times 10}{8}=5$ m