a ball thrown vertically upward with a velocity u it takes t₀ seconds to reach the highest point the distance travelled in the last t seconds of its ascend( t < t₀second)?

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Solution

velocity at the toppest point time t is zero
therefore v = u-gt
0= u-gt
u= gt
t = u/g
velocity at time t-1
v= u-g(t-1)
v= gt-gt+g
v=g
distance travelled in last one second (t = 1)
s = (velocity at time t -1)t - 1/2gt^2
= g x 1-1/2 x g x 1^2
=g/2

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(a) (t0 - t) u (b) (1/2)*(g(t0-t)²

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u

, the distance covered during the last

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, the distance covered during the last

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(Take

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)

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​​​​ a ball thrown vertically upward with a velocity u it takes t0 seconds to reach the highest point the distance travelled in the last t seconds of its ascend( t < t0 second)?

velocity at the toppest point time t is zero therefore v = u-gt 0= u-gt u= gt t = u/g velocity at time t-1 v= u-g(t-1) v= gt-gt+g v=g distance travelled in last one second (t = 1) s = (velocity at time t -1)t - 1/2gt^2 = g x 1-1/2 x g x 1^2 =g/2

a ball thrown vertically upward with a velocity u it takes t₀ seconds to reach the highest point the distance travelled in the last t seconds of its ascend( t < t₀second)?

velocity at the toppest point time t is zero
therefore v = u-gt
0= u-gt
u= gt
t = u/g
velocity at time t-1
v= u-g(t-1)
v= gt-gt+g
v=g
distance travelled in last one second (t = 1)
s = (velocity at time t -1)t - 1/2gt^2
= g x 1-1/2 x g x 1^2
=g/2