Question

A ball thrown with a velocity of $49m{s}^{-1}$ got the maximum range recorded in the atmosphere as $225m$. The decrease in range due to the atmosphere is

• A. $0m$
• B. $245m$
• C. $225m$
• D. $20m$

Answer 1

Answer: (D)

$20m$

$R_{max}=\frac{u^{2}sin2\theta }{g}|at\theta ={45}^0=\frac{u^2}{g}=\frac{{49}^2}{9.8}=245m$

But range measured $=225m$
Hence, decrease in range due to atmosphere $=245-225=20m$