A ball travellimg at a speed if 15m/s is returned by a racket in the opposite direction with a velocity of 20m/s if the change in the kinetic energy of the ball is 8.75 J find the change in its momentum

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Solution

Dear Student ,
$\frac{1}{2} m (v^{2} - u^{2}) = 8.75 \Rightarrow m (400 - 225) = 17.5 \Rightarrow m = \frac{17.5}{175} \Rightarrow m = 0.1 k g S o t h e c h a n g e i n m o m e n t u m w i l l b e, ∆ P = m v - m (- u) = m v + m u = (0.1 \times 35) = 3.5 k g m / s$
Regards

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A ball travellimg at a speed if 15m/s is returned by a racket in the opposite direction with a velocity of 20m/s if the change in the kinetic energy of the ball is 8.75 J find the change in its momentum

Dear Student , 12mv2-u2=8.75⇒m(400-225)=17.5⇒m=17.5175⇒m=0.1 kgSo the change in momentum will be,∆P=mv-m-u=mv+mu=0.1×35=3.5 kgm/s Regards

Dear Student ,
$\frac{1}{2} m (v^{2} - u^{2}) = 8.75 \Rightarrow m (400 - 225) = 17.5 \Rightarrow m = \frac{17.5}{175} \Rightarrow m = 0.1 k g S o t h e c h a n g e i n m o m e n t u m w i l l b e, ∆ P = m v - m (- u) = m v + m u = (0.1 \times 35) = 3.5 k g m / s$
Regards