A ball weighing $10 g$ hits a hard surface vertically with a speed of $5 m / s e c$ and rebounds with the same speed. The ball remains in contact with the surface for $1 / 100 s e c$ . The average force exerted by the surface on the ball is

100 N

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10 N

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1 N

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0.1 N

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Solution

The correct option is A $10 N$
Given,
$m = 10 g = 0.01 k g$
$v = 5 m / s$
$t = \frac{1}{100} s e c$
Average force, $F_{a v g} = \frac{2 m v}{t}$
$F = \frac{2 \times 0.01 \times 5}{1 / 100} = 10 N$
The correct option is B.

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A ball weighing 10g hits a hard surface vertically with a speed of 5m/sec and rebounds with the same speed. The ball remains in contact with the surface for 1/100sec. The average force exerted by the surface on the ball is

The correct option is A 10NGiven,m=10g=0.01kgv=5m/st=1100secAverage force, Favg=2mvtF=2×0.01×51/100=10NThe correct option is B.

A ball weighing $10 g$ hits a hard surface vertically with a speed of $5 m / s e c$ and rebounds with the same speed. The ball remains in contact with the surface for $1 / 100 s e c$ . The average force exerted by the surface on the ball is

The correct option is A $10 N$
Given,
$m = 10 g = 0.01 k g$
$v = 5 m / s$
$t = \frac{1}{100} s e c$
Average force, $F_{a v g} = \frac{2 m v}{t}$
$F = \frac{2 \times 0.01 \times 5}{1 / 100} = 10 N$
The correct option is B.