A ball weighing 4 kg of density $4000 k g m^{- 3}$ is completely immersed in water of density $10^{3} k g m^{- 3}$ . Find the force of buoyancy on it in $N$ . (Given $g = 10 m s^{- 2}$ )

10 N

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1 N

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0.1 N

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None of the above

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Solution

The correct option is A $10 N$
Buoyant force = weight of the liquid displaced
=volume of the ball $\times$ water density $\times$ g
Volume of ball $= \frac{m a s s}{d e n s i t y} = \frac{4}{4000} m^{3}$
$\Rightarrow \frac{1}{1000} m^{3}$

density of water $= 10^{3} k g m^{- 3}$
Buoyant force
$\Rightarrow 1000 \times \frac{1}{1000} \times g N$
$\Rightarrow 10 N$

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A ball weighing 4 kg of density 4000kgm−3 is completely immersed in water of density 103kgm−3. Find the force of buoyancy on it in N. (Given g=10ms−2)

The correct option is A 10NBuoyant force = weight of the liquid displaced=volume of the ball × water density ×gVolume of ball =massdensity=44000m3 ⇒11000m3density of water =103kgm−3Buoyant force⇒1000×11000×gN⇒10N

A ball weighing 4 kg of density $4000 k g m^{- 3}$ is completely immersed in water of density $10^{3} k g m^{- 3}$ . Find the force of buoyancy on it in $N$ . (Given $g = 10 m s^{- 2}$ )