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Question

A ball whose kinetic energy is E, is thrown at an angle of 45o with the horizontal, its kinetic energy at the highest point of its flight will be?

A
E
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B
E2
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C
E2
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D
Zero
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Solution

The correct option is C E2

The kinetic energy of the ball at the highest point is as follows:
the expression for kinetic energy is KE=12mv2.

So, the kinetic energy at the highest point is,

KEh=12m(vcos(45))2

KEh=12m(v2)(cos(45))2

KEh=E(cos(45))2

KEh=E2

so, at the highest point the kinetic energy is E2.

1013285_1091340_ans_672392efd65f456798e3c64d12b7ab31.jpg

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