A ball with momentum $0.5 k g m s^{- 1}$ coming towards a batsman is hit by him such that it goes on the same path in opposite direction with momentum $0.3 k g m s^{- 1}$ . If the time of contact of the ball with the bat is $0.02 s$ , find the force on the ball by the bat.

10 N

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40 N

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75 N

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30 N

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Solution

The correct option is B $40 N$
$F = \frac{Δ p}{Δ t} = \frac{0.5 - (- 0.3)}{0.02} = 40 N$

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A ball with momentum 0.5 kg m s−1 coming towards a batsman is hit by him such that it goes on the same path in opposite direction with momentum 0.3 kg m s−1. If the time of contact of the ball with the bat is 0.02 s, find the force on the ball by the bat.

The correct option is B 40 NF=ΔpΔt=0.5−(−0.3)0.02=40N

A ball with momentum $0.5 k g m s^{- 1}$ coming towards a batsman is hit by him such that it goes on the same path in opposite direction with momentum $0.3 k g m s^{- 1}$ . If the time of contact of the ball with the bat is $0.02 s$ , find the force on the ball by the bat.

The correct option is B $40 N$
$F = \frac{Δ p}{Δ t} = \frac{0.5 - (- 0.3)}{0.02} = 40 N$