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Standard XII

Physics

Spring Force

A balloon con...

Question

A balloon contains $1000 m^{3}$ of Hydrogen. If the mass of the balloon without gas is $100 k g$ the net lifting ability of the balloon is (in $k g - w t$ .) ( given density of Hydrogen is $0.09 k g . m^{- 3}$ and that of air is $1.3 k g . m^{- 3}$ ):

2220

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1300

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190

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1110

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Solution

The correct option is D $1110$
Net force acting upwards= Buoyant force- Weight of balloon-Weight of hydrogen
$= V ρ g - V d g - m g$
$= V (ρ - d) g - m g$
$= [1000 \times (1.3 - 0.09)] k g . w t - 100 k g . w t$
$= 1110 k g . w t$

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A balloon contains 1000m3 of Hydrogen. If the mass of the balloon without gas is 100kg the net lifting ability of the balloon is (in kg−wt.) ( given density of Hydrogen is 0.09kg.m−3 and that of air is 1.3kg.m−3):

The correct option is D 1110Net force acting upwards= Buoyant force- Weight of balloon-Weight of hydrogen=Vρg−Vdg−mg=V(ρ−d)g−mg=[1000×(1.3−0.09)]kg.wt−100kg.wt=1110kg.wt

A balloon contains $1000 m^{3}$ of Hydrogen. If the mass of the balloon without gas is $100 k g$ the net lifting ability of the balloon is (in $k g - w t$ .) ( given density of Hydrogen is $0.09 k g . m^{- 3}$ and that of air is $1.3 k g . m^{- 3}$ ):

The correct option is D $1110$
Net force acting upwards= Buoyant force- Weight of balloon-Weight of hydrogen
$= V ρ g - V d g - m g$
$= V (ρ - d) g - m g$
$= [1000 \times (1.3 - 0.09)] k g . w t - 100 k g . w t$
$= 1110 k g . w t$