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Question

A balloon contains 14.0 L of air at 760 torr.. What will be the volume of the balloon when it is taken to a depth of 10 ft in a swimming pool? Assume that the temperature of the air and water are equal (density: Hg=13.6 g/mL)

A
11.0
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B
11.3
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C
10
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D
10.8
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Solution

The correct option is D 10.8
we know, P1V1=P2V2

P = pressure

V = volume

P1= 760 torr

V1= 14 L

10ft=3.048m

Density of water (ρ)= 1000

g=9.8 m/s2

We know,
p=ρgh

So, P2=1000×9.8×3.048+101325

(we will get the value in Pascal)

In torr, we will get 984

So, V2=P1V1P2

V2=760×14984=10.8 L

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