A balloon filled with an ideal gas is taken from the surface of the sea to the depth of 100m. What will be the volume in terms of its original volume?

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Solution

Pressure at surface of sea = 760 mm Hg

= 1033.3 cm H2O

= 10.3 m H2O

Pressure at 100 m depth = 100 + 10.3 = 110.3 m H2O

Assuming temperature to constant,

P1V1 (at surface) = P2V2 (at 100 m depth)

10.3 x V1 = 110.3 x V2

V2 = 0.093 V1

= 9.3% of V1.

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A balloon filled with an ideal gas is taken from the surface of the sea to the depth of 100m. What will be the volume in terms of its original volume?

Pressure at surface of sea = 760 mm Hg = 1033.3 cm H2O = 10.3 m H2O Pressure at 100 m depth = 100 + 10.3 = 110.3 m H2O Assuming temperature to constant, P1V1 (at surface) = P2V2 (at 100 m depth) 10.3 x V1 = 110.3 x V2 V2 = 0.093 V1 = 9.3% of V1.

Pressure at surface of sea = 760 mm Hg

= 1033.3 cm H2O

= 10.3 m H2O

Pressure at 100 m depth = 100 + 10.3 = 110.3 m H2O

Assuming temperature to constant,

P1V1 (at surface) = P2V2 (at 100 m depth)

10.3 x V1 = 110.3 x V2

V2 = 0.093 V1

= 9.3% of V1.