A balloon filled with metane $C H_{4}$ is pricked with a sharp poiny and quickly plunge hydrogen at the same preasure.After sometime the balloon will have:

Enlarged

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Collapsed

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Remained unchanged in size

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Ethylene

(C_{2} H_{4})

inside it

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Enlarged
The balloon will be enlarged. It can be explained by Graham's Law of effusion.

Suggest Corrections

Similar questions

A balloon filled with methane (CH₄) is pricked with a sharp point and quickly plunged into a tank of hydrogen at the same pressure. After sometime, the balloon will have:

Q. A balloon filled with methane

C H_{4}

is pricked with a sharp point and quickly plunged into a tank of hydrogen at the same pressure. After sometime the balloon will have?

Q. A balloon filled with ethylene (molecular formula

C_{2} H_{4}

) is pricked with a sharp point and quickly plunged into a tank of hydrogen at the same pressure. After some time the balloon will :

Q. A balloon filled with ethyne is pricked with a sharp point and quickly dropped in a tank of

H_{2}

gas under identical conditions. After a while the balloon will:

Join BYJU'S Learning Program

A balloon filled with metane CH4 is pricked with a sharp poiny and quickly plunge hydrogen at the same preasure.After sometime the balloon will have:

The correct option is A EnlargedThe balloon will be enlarged. It can be explained by Graham's Law of effusion.

A balloon filled with metane $C H_{4}$ is pricked with a sharp poiny and quickly plunge hydrogen at the same preasure.After sometime the balloon will have:

The correct option is A Enlarged
The balloon will be enlarged. It can be explained by Graham's Law of effusion.