A balloon has 2 g of air. A small hole is pierced into it. The air comes out with a velocity of 4 m/s.If the balloon shrinks completely in 2.5 s. The average force acting on the balloon is
A
0.0008 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.0032 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.2 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 0.0032 N force equals to the time rate of change of momentum i.e F = P/t where P = mv (m=mass , V =velocity) F = mv/t = (0.002kg × 4 m/s)÷ 2.5 sec F = 3.2 × 10^-3 N = 0.0032 N