Question

A balloon has 8 gm of air. A small hole is pierced into it. The air escapes at a uniform rate of 7cm/s. If the balloon shrinks in 5.6 sec, then the average force acting on the balloon is

• A. ${10}^{-4}N$
• B. ${10}^{-2}dyne$
• C. $56dyne$
• D. ${10}^{6}N$

Answer 1

Answer: (A)

${10}^{-4}N$

Force acting on the balloon ,

$F=7\times \frac{8}{5.6}$
$=10dynes={10}^{-4}N$