A balloon is moving vertically upward with a velocity of 4m/s. When it is at a height of h, a body is gently released from it. If it reaches the ground in 4s, the height of the balloon, when the body is released is
A
80m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
96m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
64m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
78m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C64m As both the balloon and body are moving upwards together.
The particle initially will acquire the velocity of balloon before falling.
Assuming upward direction to be positive.
Initial velocity of balloon is +4m/s
By using second equation of motion, we get −h=4×4−1210(4)2 ⇒h=64m