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Question

# A balloon is rising vertically upwards at a velocity of 10m/s . When it is at a height of 45m from the ground,a parachutist bails out from it. After 3seconds he openshis parachute and decelerates at a constant rate of 5m/sâˆ’2. What was the height of the parachutist above the ground when he opened his parachute?(take g=10m/sâˆ’2)

A
15 m
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B
30 m
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C
45 m
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D
60 m
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Solution

## The correct option is C 30 mGiven,u=10m/s in upward direction.g=−10m/s2 in downward directiont=3secH=45mSo by second equation of motion:s=ut+12at2=10×3+12(−10)×3×3=30−45=−15mHere negative sign indicates that it is directed downwards.So height from the ground when he opened parachute is =45−15=30m

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