A balloon is rising with a constant acceleration of $2 m / s^{2}$ . At a certain instant when the balloon was moving with a velocity of $4 m / s$ , a stone was dropped from it in a region where $g = 10 m / s^{2}$ . The velocity and acceleration of stone as it comes out from the balloon are respectively (in m/s and $m / s^{2}$ )

4, 10

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4, 5

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10, 4

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None of these

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Solution

The correct option is A $4, 10$
When the stone was in the balloon, the stone had the same velocity as that of balloon. So when the stone came out of the balloon, the velocity of stone was $4 m / s$ upwards.
After coming out of the balloon, the stone was in free fall motion, so the stone experienced an acceleration due to gravity equal to $g = 10 m / s^{2}$ in downward direction.

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A stone is dropped from a rising balloon at a height of 76 m above the

ground and it reaches the ground in 6s. What was the velocity of the

balloon when the stone was dropped? Take g=10 m/ $s^{2}$ .

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g = 10 m /

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2

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(g = 10 m / s^{2})

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