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Standard XII

Physics

Tension in a String

A balloon mas...

Question

A balloon mass M is descending at a constant acceleration $α$ . When a mass m is released from the balloon. It starts rising with the same acceleration $α$ . What is the value of m?

$\frac{α}{α + g} M$

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$\frac{2 α}{α + g} M$

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$\frac{α + g}{α} M$

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$\frac{α + g}{2 α} M$

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Solution

The correct option is B
$\frac{2 α}{α + g} M$

$M g - F = M a . . . . (1) F - (M - m) g = (M - m) a . . . . (2) From (1) and (2) m = [\frac{2 α}{α + g}] M$

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A balloon mass M is descending at a constant acceleration α. When a mass m is released from the balloon. It starts rising with the same acceleration α. What is the value of m?

The correct option is B 2αα+gM Mg−F=Ma....(1)F−(M−m)g=(M−m)a....(2)From (1) and (2)m=[2αα+g]M

A balloon mass M is descending at a constant acceleration $α$ . When a mass m is released from the balloon. It starts rising with the same acceleration $α$ . What is the value of m?

The correct option is B
$\frac{2 α}{α + g} M$

$M g - F = M a . . . . (1) F - (M - m) g = (M - m) a . . . . (2) From (1) and (2) m = [\frac{2 α}{α + g}] M$